(x)=4^4-64x^2

Solution for (x)=4^4-64x^2 equation:

(x)=4^4-64x^2

We move all terms to the left:

(x)-(4^4-64x^2)=0

We get rid of parentheses

64x^2+x-4^4=0

We add all the numbers together, and all the variables

64x^2+x-256=0

a = 64; b = 1; c = -256;
Δ = b2-4ac
Δ = 12-4·64·(-256)
Δ = 65537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{65537}}{2*64}=\frac{-1-\sqrt{65537}}{128}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{65537}}{2*64}=\frac{-1+\sqrt{65537}}{128}
$